-x^2+5x-50=0

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Solution for -x^2+5x-50=0 equation:


Simplifying
-1x2 + 5x + -50 = 0

Reorder the terms:
-50 + 5x + -1x2 = 0

Solving
-50 + 5x + -1x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
50 + -5x + x2 = 0

Move the constant term to the right:

Add '-50' to each side of the equation.
50 + -5x + -50 + x2 = 0 + -50

Reorder the terms:
50 + -50 + -5x + x2 = 0 + -50

Combine like terms: 50 + -50 = 0
0 + -5x + x2 = 0 + -50
-5x + x2 = 0 + -50

Combine like terms: 0 + -50 = -50
-5x + x2 = -50

The x term is -5x.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5x + 6.25 + x2 = -50 + 6.25

Reorder the terms:
6.25 + -5x + x2 = -50 + 6.25

Combine like terms: -50 + 6.25 = -43.75
6.25 + -5x + x2 = -43.75

Factor a perfect square on the left side:
(x + -2.5)(x + -2.5) = -43.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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